I guess that I am not closing my PyQT5 Window correctly. I am using spyder (3.3.5) which I have installed with anaconda, to program a pyqt5 program. I am using qt creator to design my ui file, which I load using the loadUi function in pyqt package. Everything works fine with the code, until I need to close it. I close the window via the close button (the x button in the top right). The window itself is closed, but it seems like the console (or shell) is stuck, and I can't give it further commands or to re run the program, without having to restart the kernel (to completely close my IDE and re opening it).
I have tried looking for solutions to the problem in the internet, but none seems to work for me. Including changing the IPython Console > Graphics to automatic.
Edit: Also Created an issure: https://github.com/spyder-ide/spyder/issues/9991
import sys
from PyQt5 import QtWidgets,uic
from PyQt5.QtWidgets import QMainWindow
class Mic_Analysis(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.ui=uic.loadUi("qt_test.ui",self)
...
if __name__ == "__main__":
def run_app():
if not QtWidgets.QApplication.instance():
app = QtWidgets.QApplication(sys.argv)
else:
app=QtWidgets.QApplication.instance()
mainWin=Mic_Analysis()
mainWin.show()
app.exec_()
run_app()
If someone have any suggestion I would be very happy to hear them.
For me, it helped to remove the 'app.exec_()' command. But then it closes immediatly when running the code. To keep the window open, I needed to return the MainWindow instance to the global scope (or make it a global object). My code looks like this:
from PyQt5 import QtWidgets
import sys
def main():
if not QtWidgets.QApplication.instance():
app = QtWidgets.QApplication(sys.argv)
else:
app = QtWidgets.QApplication.instance()
main = MainWindow()
main.show()
return main
if __name__ == '__main__':
m = main()
Try adding :
app.setQuitOnLastWindowClosed(True)
to your main() function
def main():
app = QApplication(sys.argv)
app.setQuitOnLastWindowClosed(True)
win = MainWindow()
win.show()
sys.exit(app.exec_())
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