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Calculating Levenshtein Distance permitting QWERTY errors in R [closed]

I'm looking to calculate the Levenshtein distance in R between user-inputted company names against the Fortune 1000 list, but allowing for QWERTY typographical errors. For instance, Mcdimldes should have a distance of 2 from McDonalds because i is next to o and m is next to n.

There was this other attempt at an implementation but in Python (click here). Any help is greatly appreciated.

Please let me know if additional details should be added to clarify the problem.

like image 668
Jonathan Rauscher Avatar asked Jan 31 '26 14:01

Jonathan Rauscher


1 Answers

Maybe you can build something up on this:

## from the link in the linked python answer:
# txt <- "'q': {'x':0, 'y':0}, 'w': {'x':1, 'y':0}, 'e': {'x':2, 'y':0}, 'r': {'x':3, 'y':0}, 't': {'x':4, 'y':0}, 'y': {'x':5, 'y':0}, 'u': {'x':6, 'y':0}, 'i': {'x':7, 'y':0}, 'o': {'x':8, 'y':0}, 'p': {'x':9, 'y':0}, 'a': {'x':0, 'y':1},'z': {'x':0, 'y':2},'s': {'x':1, 'y':1},'x': {'x':1, 'y':2},'d': {'x':2, 'y':1},'c': {'x':2, 'y':2}, 'f': {'x':3, 'y':1}, 'b': {'x':4, 'y':2}, 'm': {'x':5, 'y':2}, 'j': {'x':6, 'y':1}, 'g': {'x':4, 'y':1}, 'h': {'x':5, 'y':1}, 'j': {'x':6, 'y':1}, 'k': {'x':7, 'y':1}, 'l': {'x':8, 'y':1}, 'v': {'x':3, 'y':2}, 'n': {'x':5, 'y':2}"
# txt <- strsplit(txt, "\\},\\s?")[[1]]
# m <- t(sapply(regmatches(txt, regexec("'(.)':\\s*\\{'x':(\\d+),\\s*'y':(\\d+).*", txt)), "[", -1))
# m <- matrix(as.numeric(m[,-1]), ncol=2, dimnames = list(m[,1],c("x","y")))
# dput(m)
m <- structure(c(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 0, 1, 1, 2, 2, 3, 
  4, 5, 6, 4, 5, 6, 7, 8, 3, 5, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 
  2, 1, 2, 1, 2, 1, 2, 2, 1, 1, 1, 1, 1, 1, 2, 2), .Dim = c(27L, 
  2L), .Dimnames = list(c("q", "w", "e", "r", "t", "y", "u", "i", 
  "o", "p", "a", "z", "s", "x", "d", "c", "f", "b", "m", "j", "g", 
  "h", "j", "k", "l", "v", "n"), c("x", "y")))
m["m", ] <- c(6,2) # 5,2 seems wrong...

f <- function(a, b) {
  posis <- lapply(strsplit(c(a, b), "", T), function(x) m[x,,drop=F])
  d <- abs(posis[[1]]-posis[[2]])
  idx <- which(rowSums(d>1)==0)
  if (length(idx)>0) rownames(posis[[1]])[idx] <- rownames(posis[[2]])[idx]
  paste(rownames(posis[[1]]), collapse="")
}
a <- tolower("Mcdimldes") # make it case-insensitive
b <- tolower("McDonalds")
adist(a,b) # regular distance
# [1,]    4
newa <- f(a, b) # replace possible typo chars
adist(newa,b) # new dist is 2 - as requested
#      [,1]
# [1,]    2

The keyboard layout in the matrix:

keyb <- sweep(m, 2, c(1, -1), "*")
plot(keyb, type = "n")
text(keyb, rownames(keyb))
grid()

enter image description here

like image 103
lukeA Avatar answered Feb 02 '26 05:02

lukeA



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