bash while string is not empty

Question

I'm trying to set up a script that parses a string.

My loop is currently

while [ -n "$RAW" ]; do
    // do some processing here
    RAW=$(echo $RAW| sed -r 's/^.{15}//')
done

However, the script never seems to end

Answer 1

It is not ending because the sed expression is not correct. It expects minimum 15 characters and does not work for anything less than 15 chars. Try this:

RAW=$(echo $RAW| sed -r 's/^.{0,15}//')

Answer 2

Maybe you just want this:

#!/bin/bash
RAW=012345678901234567890
.
.
.
RAW=${RAW:15}
echo $RAW
567890