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Bash validate date

I'm writing a shell script and am confused as to why my date validation code is not working. I tried the following solutions to similar questions I found, but is_valid is always set to 1:

date "+%m/%d/%Y" -d "$1" 2>1 > /dev/null
//or..
date -d "2012-02-29" > /dev/null 2>&1
is_valid=$?
#always set to 1, even when given a valid date

How do I correctly validate the date format? The date should only be valid if in the format MM/DD/YYYY

I also tried this solution: Linux Bash - Date Format but it always rejected the date as well.

like image 383
Cbas Avatar asked Oct 21 '25 06:10

Cbas


1 Answers

The BSD date that ships with Mac OS X doesn't support the -d option (or rather, it uses -d for something entirely different). Either install GNU date, or use the following to validate your input string:

date -f "%Y-%m-%d" -j "2012-02-29" >/dev/null 2>&1

The -f provides the input format, and the -j tells date to simply output the date, not attempt to set the system clock.

like image 71
chepner Avatar answered Oct 22 '25 21:10

chepner



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