I have a csv like
A,B,C,D
1,2,,
1,2,30,100
1,2,40,100
4,5,,
4,5,60,200
4,5,70,200
8,9,,
In row 1 and row 4 C value is missing (NaN). I want to take their value from row 2 and 5 respectively. (First occurrence of same A,B value).
If no matching row is found, just put 0 (like in last line) Expected op:
A,B,C,D
1,2,30,
1,2,30,100
1,2,40,100
4,5,60,
4,5,60,200
4,5,70,200
8,9,0,
using fillna I found bfill: use NEXT valid observation to fill gap but the NEXT observation has to be taken logically (looking at col A,B values) and not just the upcoming C column value
You'll have to call df.groupby on A and B first and then apply the bfill function:
In [501]: df.C = df.groupby(['A', 'B']).apply(lambda x: x.C.bfill()).reset_index(drop=True)
In [502]: df
Out[502]:
A B C D
0 1 2 30 NaN
1 1 2 30 100.0
2 1 2 40 100.0
3 4 5 60 NaN
4 4 5 60 200.0
5 4 5 70 200.0
6 8 9 0 NaN
You can also group and then call dfGroupBy.bfill directly (I think this would be faster):
In [508]: df.C = df.groupby(['A', 'B']).C.bfill().fillna(0).astype(int); df
Out[508]:
A B C D
0 1 2 30 NaN
1 1 2 30 100.0
2 1 2 40 100.0
3 4 5 60 NaN
4 4 5 60 200.0
5 4 5 70 200.0
6 8 9 0 NaN
If you wish to get rid of NaNs in D, you could do:
df.D.fillna('', inplace=True)
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