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AttributeError: Can't pickle local object '<locals>.<lambda>' [duplicate]

I am trying to pickle a nested dictionary which is created using:

collections.defaultdict(lambda: collections.defaultdict(int))

My simplified code goes like this:

class A:
  def funA(self):
    #create a dictionary and fill with values
    dictionary = collections.defaultdict(lambda: collections.defaultdict(int))
    ...
    #then pickle to save it
    pickle.dump(dictionary, f)

However it gives error:

AttributeError: Can't pickle local object 'A.funA.<locals>.<lambda>'

After I print dictionary it shows:

defaultdict(<function A.funA.<locals>.<lambda> at 0x7fd569dd07b8> {...}

I try to make the dictionary global within that function but the error is the same. I appreciate any solution or insight to this problem. Thanks!

like image 967
zurich_ruby Avatar asked Sep 13 '25 19:09

zurich_ruby


1 Answers

pickle records references to functions (module and function name), not the functions themselves. When unpickling, it will load the module and get the function by name. lambda creates anonymous function objects that don't have names and can't be found by the loader. The solution is to switch to a named function.

def create_int_defaultdict():
    return collections.defaultdict(int)

class A:
  def funA(self):
    #create a dictionary and fill with values
    dictionary = collections.defaultdict(create_int_defaultdict)
    ...
    #then pickle to save it
    pickle.dump(dictionary, f)
like image 183
tdelaney Avatar answered Sep 15 '25 08:09

tdelaney