Lets assume I have a simple code:
import asyncio
async def exc():
print(1 / 0)
loop = asyncio.get_event_loop()
loop.create_task(exc())
try:
loop.run_forever()
except KeyboardInterrupt:
loop.stop()
loop.close()
If I run it, I get error message immediately
Task exception was never retrieved
future: <Task finished coro=<exc() done, defined at qq.py:4> exception=ZeroDivisionError('division by zero',)>
Traceback (most recent call last):
File "qq.py", line 5, in exc
print(1 / 0)
ZeroDivisionError: division by zero
But, if I change loop.create_task(exc()) to task = loop.create_task(exc())
I'll get the same error message after click ctrl+c
Why does task assignment change the time of output of error?
A Exception in the Task (of underlying asyncio.Future to be precise) can be retrieved with Future.exception(). If it's not retrieved, the exception will be handled at release of the Future object with eventloop's call_exception_handler.
So, as @dirn pointed, while the Task has reference (assigned to variable in your case) it's not going be freed, therefore del task_future won't be called, loop's handler won't be executed either.
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