I have a union in a project i'm working on that represents a USB joystick report:
union {
struct{
uint8_t xaxis;
uint8_t yaxis;
uint8_t xraxis;
uint8_t yraxis;
uint8_t zraxis;
uint8_t slider;
uint8_t buttons8;
uint8_t buttons16;
};
uchar buffer[8];
} report;
this way i can easily put the values into the struct members and use the buffer member to send that data over USB, however I end up modifying this union for different projects (different resolutions on the axis, more/less buttons etc) so then i have to work out what the new size of the struct is to declare the array with the same size.
is there a way to automatically make the array the same size? i thought of using sizeof
which requires me to change the struct like this:
union {
struct _data{ // either this
uint8_t xaxis;
uint8_t yaxis;
uint8_t xraxis;
uint8_t yraxis;
uint8_t zraxis;
uint8_t slider;
uint8_t buttons8;
uint8_t buttons16;
} data; // or this
uchar buffer[8];
} report;
but then i can no longer put data into the struct like this:
report.xaxis = value;
but instead:
report.data.xaxis = value;
which i don't want.
is there a way to do this cleanly?
Step 1 is to get a standard C compiler. Then you can use an anonymous struct. To get the appropriate size for the array, use a struct tag, which is only needed internally by the union.
typedef union {
struct data {
uint8_t xaxis;
uint8_t yaxis;
uint8_t xraxis;
uint8_t yraxis;
uint8_t zraxis;
uint8_t slider;
uint8_t buttons8;
uint8_t buttons16;
};
uint8_t buffer[sizeof(struct data)];
} report_t;
...
report_t r;
r.xaxis = 123;
You could use offsetof()
for this with the last element in the struct
union
{
struct data
{
uint8_t xaxis;
uint8_t yaxis;
uint8_t xraxis;
uint8_t yraxis;
uint8_t zraxis;
uint8_t slider;
uint8_t buttons8;
uint8_t buttons16;
};
uint8_t buffer[offsetof(struct data, buttons16)+1];
} report;
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