Appending a list in another list

Question

I don't know how these two things are working, and their outputs. And if there is any better way to do the same work.

Code 1:

A = []
s = []
for i in range(0,int(input())):
    name = input()
    score = float(input())
    s.append(name)
    s.append(score)
    A.append(s)
    s = []
print(A)

Output 1:

[['firstInput', 23.33],['secondInput',23.33]]

Code 2:

A = []
s = []
for i in range(0,int(input())):
    name = input()
    score = float(input()) 
    s.append(name)
    s.append(score)
    A.append(s)
    s.clear()
print(A)

Output 2:

[[],[]]

Answer 1

There are better ways to do this, but you don't need list s at all.

A = []

for i in range(0,int(input())):
    name = input()
    score = float(input())

    A.append([name,score])

print(A)

Answer 2

That's the expected list behavior. Python uses references to store elements in list. When you use append, it simply stored reference to s in A. When you clear the list s it will show up as blank in A as well. You can use the copy method if you want to make an independent copy of the list s in A.