It's past several days since I started using this function and have not yet succeeded in obtaining valid results.
What i want is basically convert acceleration vector from device's coordinates system, to real world coordinates. I' know that is possible because i have acceleration in relative coordinates and i know the orientation of the device in real world system.
Reading Android developers seems that using getRotationMatrix() i get R = rotation matrix.
So if i want A (acceleration vector in world system) from A' (acceleration vector in phone system) i must do simply:
A=R*A'
But i cant'n understand why the vector A has ALWAYS the first and the second component zero (example: +0,00;-0,00;+6,43)
My current code is similar to this:
public void onSensorChanged(SensorEvent event) {
synchronized (this) {
switch(event.sensor.getType()){
case Sensor.TYPE_ACCELEROMETER:
accelerometervalues = event.values.clone();
break;
case Sensor.TYPE_MAGNETIC_FIELD:
geomagneticmatrix =event.values.clone();
break;
}
if (geomagneticmatrix != null && accelerometervalues != null) {
float[] Rs = new float[16];
float[] I = new float[16];
SensorManager.getRotationMatrix(Rs, I, accelerometervalues, geomagneticmatrix);
float resultVec[] = new float[4];
float relativacc[]=new float [4];
relativacc[0]=accelerationvalues[0];
relativacc[1]=accelerationvalues[1];
relativacc[2]=accelerationvalues[2];
relativacc[3]=0;
Matrix.multiplyMV(resultVec, 0, Rs, 0, relativacc, 0);
//resultVec[] is the vector acceleration relative to world coordinates system..but doesn't WORK!!!!!
}
}
}
This question is very similar to this one Transforming accelerometer's data from device's coordinates to real world coordinates but there i can't find the solution...i had tried all the ways..
Please help me, i need help!!!
UPDATE:
Now my code is below, i had tried to explain matrix product, but nothing change:
float[] Rs = new float[9];
float[] I = new float[9];
SensorManager.getRotationMatrix(Rs, I, accelerationvalues, geomagneticmatrix);
float resultVec[] = new float[4];
resultVec[0]=Rs[0]*accelerationvalues[0]+Rs[1]*accelerationvalues[1]+Rs[2]*accelerationvalues[2];
resultVec[1]=Rs[3]*accelerationvalues[0]+Rs[4]*accelerationvalues[1]+Rs[5]*accelerationvalues[2];
resultVec[2]=Rs[6]*accelerationvalues[0]+Rs[7]*accelerationvalues[1]+Rs[8]*accelerationvalues[2];
Here some example of data read and result:
Rs separated by " " Rs[0] Rs[1]....Rs[8]
Av separated by " " accelerationvalues[0] ...accelerationvalues[2]
rV separated by " " resultVec[0] ...resultVec[2]

As you can notice the component on x and y axes in real world are zero (around) even if you move speddy the phone. Instead the relative acceleration vector detect correctly each movement!!!
SOLUTION The errors in the numberrs are relative to float vars multiplication that is not the same as a double multyplication. This sums to the fact that rotation matrix isn't costant if the phone, even if with the same orientation, is accelerating. So is impossible translate acceleration vector to absolute coordinates during motion... It's hard but it's the reality.
Finnaly i found the answer:
The errors in the numbers are relative to float vars multiplication that is not the same as a double multyplication. Here there is the solution. This sums to the fact that rotation matrix isn't costant if the phone, even if with the same orientation, is accelerating. So is impossible translate acceleration vector to absolute coordinates during motion... It's hard but it's the reality.
FYI the orientation vector is made from magnetomer data AND gravity vector. This cause a ciclic problem: convert relative acc needs oirentation needs magnetic field AND gravity, but we know gravity only if the phone is stop by relative acc..so we are return to begin.
This is confirmed in Android Developers where is explained that rotation matrix give true result only when the phone isn't accelerate (e.g. they talk of free fall, infact there shouldn't be gravity mesaurement) or when it isn't in a non regulare magnetic field.
The matrices returned by this function are meaningful only when the device is not free-falling and it is not close to the magnetic north. If the device is accelerating, or placed into a strong magnetic field, the returned matrices may be inaccurate.
In others world, fully un-useful... You can trust this thing doing simple experiment on the table with Android Senor or something like this..
You must track down this arithmetic error before you worry about rotation, acceleration or anything else.
You have confirmed that
resultVec[0]=Rs[0]*accelerationvalues[0];
gives you
Rs[0]: 0.24105562
accelerationValues[0]: 6.891896
resultVec[0]: 1.1920929E-7
So once again, simpify. Try this:
Rs[0] = 0.2;
resultVec[0] = Rs[0] * 6.8
EDIT:
The last one gave resultVec[0]=1.36, so let's try this:
Rs[0] = 0.2;
accelerationValues[0] = 6.8
resultVec[0] = Rs[0] * accelerationValues[0];
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With