The scenario is - I read the last line of a file, increment it by one and write it back.
The read and write has been done. I am finding it difficult to increment the alpha-numberic values as it has a few conditions.
The conditions are:
What I am doing now is separating the alphabets and integers, incrementing it and concatenating them back.
The code so far:
String[] part = lastLine.split("(?<=\\D)(?=\\d)");
System.out.println(part[0]);
System.out.println(part[1]);
int numberOnly = Integer.parseInt(lastLine.replaceAll("[^0-9]", ""));
numberOnly++;
String lettersOnly = lastLine.replaceAll("[^A-Z]", "");
if (lettersOnly.length() > 1){
String lastLetter = lettersOnly.substring(lettersOnly.length() - 1);
if(lastLetter.equalsIgnoreCase("Z") && number.equalsIgnoreCase("9") ){
String notLastLetter = lettersOnly.substring(lettersOnly.length() - 2);
char d = lettersOnly.charAt(0);
d++;
System.out.println("Letters after increment more tan two : " +d);
lettersOnly = Character.toString(d) + "Z";
}
}
else{
}
System.out.println("Letters after increment : " +lettersOnly);
Any help would be greatly appreciated.
public class AlphaNumericCounter {
String[] part;
int counter; //Variable storing numeric part of counter
String alpha; //Variable storing Alpha part of counter
static String final_output = "A00"; // First Input considered as A00 and also the variable which will be store each count
static boolean continueIncrement = true; //For running the loop till we reach ZZ9
/* Def constructor */
public AlphaNumericCounter() {
}
/* Constructor called from main method with primary input A00 */
public AlphaNumericCounter(String number) {
part = number.split("(?<=\\D)(?=\\d)");
}
/* Function called each time from inside loop to generate next alphanumeric count */
public void increment() {
part = final_output.split("(?<=\\D)(?=\\d)");
counter = Integer.valueOf(part[1]) + 1;
alpha = part[0];
}
public String toString() {
if (alpha.length() == 1){
if (String.valueOf(counter).length() > 2){
if ((int)alpha.charAt(0) + 1 > 90/*If Z encountered*/){
alpha = "AA";
}else{
alpha = String.valueOf((char)((int)alpha.charAt(0) + 1));//Take Next Alphabet
}
counter = 1; //Reset counter to 1
}
}else{
//We have AA, AB ... ZZ format of alpha
if (String.valueOf(counter).length() > 1){
if ((int)alpha.charAt(0) + 1 > 90 && (int)alpha.charAt(1) + 1 > 90){
continueIncrement = false;
System.out.println("NO MORE COMBINATION AVAILABLE"); //We reached ZZ
return "";
}else if ((int)alpha.charAt(1) + 1 <= 90){
alpha = String.valueOf((char)((int)alpha.charAt(0))) + String.valueOf((char)((int)alpha.charAt(1) + 1));
counter = 1;
}else if ((int)alpha.charAt(1) + 1 > 90){
if ((int)alpha.charAt(0) + 1 <= 90){
alpha = String.valueOf((char)((int)alpha.charAt(0) + 1)) + "A";
counter = 1;
}
}
}
}
generateString();
return final_output;
}
private void generateString(){
int l1 = String.valueOf(counter).length();
int l2 = alpha.length();
final_output = alpha + (l2 == 1 && l1 == 1 ? "0" : "") + String.valueOf(counter);
}
public static void main(String[] args) {
AlphaNumericCounter lic = new AlphaNumericCounter(final_output);
while (continueIncrement){
lic.increment();
System.out.println(lic);
}
}
}
What about incrementing each "digit" separatly from right to left and handle overvlow to the next digit:
String number;//number - is your originally string
char[] digits = number.toCharArray();
boolean overflow = true;
for(int i = 2; i >= 0; i--){
if(overflow){
switch(digits[i]){
case 'Z':
digits[i] = '0';
overflow = true;
break;
case '9':
digits[i] = 'A';
overflow = false;
break;
default:
digits[i]++;
overflow = false;
}
}
}
if(overflow){
//handle ZZZ overflow here
}
String result = new String(digits);
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