How to scrape JSON file from url and print contents

Question

Here is the website I want to scrape: https://s2.coinmarketcap.com/generated/search/quick_search.json

I have no idea how to scrape the JSON file from the URL and print out the contents. I tried reading around, but the most I got was this code, which doesn't work when I run it:

import requests
import json

url = "https://s2.coinmarketcap.com/generated/search/quick_search.json"
r = requests.get(url)
cont = json.loads(r.content)
print(cont)

Answer 1

Almost correct. Should be r.json(). Requests has a built in json parser.

import requests
import json

url = "https://s2.coinmarketcap.com/generated/search/quick_search.json"
r = requests.get(url)
cont = r.json()
print(cont)

Also if you want to print the specific contents just iterate over it like you would any other json obj

for k in cont:
    if k['name'] == 'VapersCoin':
        do_something()

Answer 2

Looks like you ran into string hell. Sometimes with Python3 you have to do encode() or decode() to convert byte strings to unicode strings.

In your sample code, if you change line 6 to

cont = json.loads(r.content.decode())

it will run. @PhilippeT 's solution is also fine, as the json() function seems to automatically return a unicode string.