I'm trying to reverse a string, but it just stays the same. I don't use any modules except <string.h> and <stdio.h>.
void rev(s){
char i, temp;
char *sf = s;
char ri = strlen((s) - 1);
char *sl = &s[ri];
for (i = 0; i < ri; i++){
if (*sf != *sl){
temp = *sf++;
s[i] = *sl--; //
s[ri--] = temp; //those two seems to be getting new characters, but it won't
}
else {
ri--;
sf++;
sl--;
}
}
printf("%s", s);
}
The function will not compile at least because the parameter does not have a type specifier.
void rev(s){
The type char has a little range of acceptable values. So you shall not use it for calculating the length of a string.
The call of strlen in this declaration
char ri = strlen((s) - 1);
invokes undefined behavior. It seems you mean
char ri = strlen(s) - 1;
that also can invoke undefined behavior for an empty string.
This loop
for (i = 0; i < ri; i++){
does not use pointers.
The function can be defined the following way as it is shown in the demonsytrative program below.
#include <stdio.h>
#include <string.h>
char * reverse( char *s )
{
if ( *s )
{
for ( char *first = s, *last = s + strlen( s ); first < --last; ++first )
{
char c = *first;
*first = *last;
*last = c;
}
}
return s;
}
int main( void )
{
char s1[] = "1";
char s2[] = "12";
char s3[] = "123";
puts( reverse( s1 ) );
puts( reverse( s2 ) );
puts( reverse( s3 ) );
}
The program output is
1
21
321
A simple solution:
char *sl = sf;
while (*sl != 0)
++ sl;
-- sl;
while (sf < sl)
{
char c = *sf;
*sf = *sl;
*sl = c;
++sf, --sl;
}
Find the end of the string by skipping all characters until you find the NUL (zero) character.
Then step back one character (decrement sl) so that you have pointers to the first and the last character of the string.
Then walk both pointers towards one another and swap characters until the pointers meet or cross.
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