How to register UDF with no argument in Pyspark

Question

I have tried Spark UDF with parameter using lambda function and register it. but how could I create udf with not argument and registrar it I have tried this my sample code will expected to show current time

from datetime import datetime from pyspark.sql.functions import udf

def getTime():
    timevalue=datetime.now()
    return timevalue 

udfGateTime=udf(getTime,TimestampType())

But PySpark is showing

NameError: name 'TimestampType' is not defined

which probably means my UDF is not registered I was comfortable with this format

spark.udf.register('GATE_TIME', lambda():getTime(), TimestampType())

but does lambda function take empty argument? Though I didn't try it, I am a bit confused. How could I write the code for registering this getTime() function?

Answer 1

• lambda expression can be nullary. You're just using incorrect syntax:

  spark.udf.register('GATE_TIME', lambda: getTime(), TimestampType())
  

• There is nothing special in lambda expressions in context of Spark. You can use getTime directly:

  spark.udf.register('GetTime', getTime, TimestampType())
  

• There is no need for inefficient udf at all. Spark provides required function out-of-the-box:

  spark.sql("SELECT current_timestamp()")
  

  or

  from pyspark.sql.functions import current_timestamp
  
  spark.range(0, 2).select(current_timestamp())
  

Answer 2

I have done a bit tweak here and it is working well for now

import datetime
from pyspark.sql.types import*

def getTime():
    timevalue=datetime.datetime.now()
    return timevalue
def GetVal(x):
    if(True):
     timevalue=getTime()
     return timevalue
spark.udf.register('GetTime', lambda(x):GetVal(x),TimestampType()) 
spark.sql("select GetTime('currenttime')as value ").show()

instead of currenttime any value can pass at it will give current date time here