Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to get csv file object from zipobject in jszip and angularjs

I am trying to get csv file object from zipobject which i extracted from a zip file using jszip.But Now i am not able to read the actual csv file from this zipobject.Can anybody help? this is my zipobject,enter image description here

<!DOCTYPE html>
<html data-ng-app="myApp">

<head>

  <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js"></script>
  <script data-require="[email protected]" data-semver="2.4.0" src="https://cdn.rawgit.com/Stuk/jszip/v2.4.0/dist/jszip.js"></script>
</head>

<body data-ng-controller="testController">


  <div>
    <input type="file" name="archiveUpload" id="archiveUpload01">
  </div>

  <script>
    angular
      .module('myApp', [])
      .run(function($rootScope) {
        $rootScope.title = 'myTest Page';
      })
      .controller('testController', ['$scope', '$q',
        function($scope, $q) {

          $scope.extractArchive = function(zipfile) {
            var dfd = $q.defer();
            var reader = new FileReader();

            reader.onerror = dfd.reject.bind(dfd);
            reader.onload = function(e) {
              if (!reader.result) dfd.reject(new Error("Unknown error"));

              var zip = new JSZip(reader.result);
              return dfd.resolve(zip);
            };
            reader.readAsArrayBuffer(zipfile);
            return dfd.promise;
          }

          function onArchiveChange(evt) {
            var target = evt.dataTransfer || evt.target;
            var file = target && target.files && target.files[0];
            $scope.extractArchive(file)
              .then(function(zipFile) {
                console.log(zipFile)
              })
          }

          angular.element(document.querySelector('#archiveUpload01')).on('change', onArchiveChange);


        }
      ])
  </script>
</body>

</html>

This is my code.

like image 509
Nikhil Mohanan Avatar asked Oct 15 '25 15:10

Nikhil Mohanan


1 Answers

Use the async method to get a promise of the content (which behave like $q):

zip.file("Positions.csv").async("text")
.then(function success(txt) {
  console.log("csv is", txt);
}, function error(e) {
  console.error(e);
});

Edit: the code above is for JSZip v3, you use JSZip v2:

var txt = zip.file("Positions.csv").asText();
console.log("csv is", txt);

zip.file("Positions.csv") will give you the ZipObject you show on your image.

Edit 2: extractArchive, written for JSZip v3, looks like:

$scope.extractArchive = function(zipfile) {
  return JSZip.loadAsync(zipfile); // JSZip v3 can read Blobs and Files
}; // returns a promise of a JSZip instance

You can then chain other promises:

$scope.extractArchive(zipfile).then(function (zip) {
  return zip.file("Positions.csv").async("arraybuffer");
}).then(function (buf) {
  var blob = new Blob([buf]);
  // ...
})
like image 129
David Duponchel Avatar answered Oct 18 '25 06:10

David Duponchel



Donate For Us

If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!