I want to get a 2-D torch.Tensor with size [a,b] filled with values from a uniform distribution (in range [r1,r2]) in PyTorch.
If U is a random variable uniformly distributed on [0, 1], then (r1 - r2) * U + r2 is uniformly distributed on [r1, r2].
Thus, you just need:
(r1 - r2) * torch.rand(a, b) + r2 Alternatively, you can simply use:
torch.FloatTensor(a, b).uniform_(r1, r2) To fully explain this formulation, let's look at some concrete numbers:
r1 = 2 # Create uniform random numbers in half-open interval [2.0, 5.0) r2 = 5 a = 1 # Create tensor shape 1 x 7 b = 7 We can break down the expression (r1 - r2) * torch.rand(a, b) + r2 as follows:
torch.rand(a, b) produces an a x b (1x7) tensor with numbers uniformly distributed in the range [0.0, 1.0).x = torch.rand(a, b) print(x) # tensor([[0.5671, 0.9814, 0.8324, 0.0241, 0.2072, 0.6192, 0.4704]]) (r1 - r2) * torch.rand(a, b) produces numbers distributed in the uniform range [0.0, -3.0)print((r1 - r2) * x) tensor([[-1.7014, -2.9441, -2.4972, -0.0722, -0.6216, -1.8577, -1.4112]]) (r1 - r2) * torch.rand(a, b) + r2 produces numbers in the uniform range [5.0, 2.0)print((r1 - r2) * x + r2) tensor([[3.2986, 2.0559, 2.5028, 4.9278, 4.3784, 3.1423, 3.5888]]) Now, let's break down the answer suggested by @Jonasson: (r2 - r1) * torch.rand(a, b) + r1
torch.rand(a, b) produces (1x7) numbers uniformly distributed in the range [0.0, 1.0).x = torch.rand(a, b) print(x) # tensor([[0.5671, 0.9814, 0.8324, 0.0241, 0.2072, 0.6192, 0.4704]]) (r2 - r1) * torch.rand(a, b) produces numbers uniformly distributed in the range [0.0, 3.0).print((r2 - r1) * x) # tensor([[1.7014, 2.9441, 2.4972, 0.0722, 0.6216, 1.8577, 1.4112]]) (r2 - r1) * torch.rand(a, b) + r1 produces numbers uniformly distributed in the range [2.0, 5.0)print((r2 - r1) * x + r1) tensor([[3.7014, 4.9441, 4.4972, 2.0722, 2.6216, 3.8577, 3.4112]]) In summary, (r1 - r2) * torch.rand(a, b) + r2 produces numbers in the range [r2, r1), while (r2 - r1) * torch.rand(a, b) + r1 produces numbers in the range [r1, r2).
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