How to find second highest salary in below array list using Java8 streams [closed]

Question

class Employee
{
    int id;
     
    String name;
     
    int age;
     
    String gender;
     
    String department;
     
    int yearOfJoining;
     
    double salary;
     
    public Employee(int id, String name, int age, String gender, String department, int yearOfJoining, double salary) 
    {
        this.id = id;
        this.name = name;
        this.age = age;
        this.gender = gender;
        this.department = department;
        this.yearOfJoining = yearOfJoining;
        this.salary = salary;
    }
     
    public int getId() 
    {
        return id;
    }
     
    public String getName() 
    {
        return name;
    }
     
    public int getAge() 
    {
        return age;
    }
     
    public String getGender() 
    {
        return gender;
    }
     
    public String getDepartment() 
    {
        return department;
    }
     
    public int getYearOfJoining() 
    {
        return yearOfJoining;
    }
     
    public double getSalary() 
    {
        return salary;
    }
     
    @Override
    public String toString() 
    {
        return "Id : "+id
                +", Name : "+name
                +", age : "+age
                +", Gender : "+gender
                +", Department : "+department
                +", Year Of Joining : "+yearOfJoining
                +", Salary : "+salary;
    }
}

---

List<Employee> employeeList = new ArrayList<Employee>();
         
employeeList.add(new Employee(111, "Jiya Brein", 32, "Female", "HR", 2011, 25000.0));
employeeList.add(new Employee(122, "Paul Niksui", 25, "Male", "Sales And Marketing", 2015, 13500.0));
employeeList.add(new Employee(133, "Martin Theron", 29, "Male", "Infrastructure", 2012, 18000.0));
employeeList.add(new Employee(144, "Murali Gowda", 28, "Male", "Product Development", 2014, 32500.0));
employeeList.add(new Employee(155, "Nima Roy", 27, "Female", "HR", 2013, 22700.0));

Optional<Employee> emp = employeeList.stream()
        .collect(Collectors.maxBy(Comparator.comparingDouble(Employee::getSalary)));

Answer 1

After sorting the list according to salary in reverse order, you can skip the highest with skip(1) then get the first employee after that with findFirst() method to find the second highest salary.

Try this:

Optional<Employee> emp = employeeList.stream()
        .sorted(Comparator.comparingDouble(Employee::getSalary).reversed()).skip(1).findFirst();

System.out.println(emp.get());

Output:

Id : 111, Name : Jiya Brein, age : 32, Gender : Female, Department : HR, Year Of Joining : 2011, Salary : 25000.0

Answer 2

you need to sort the list, then get 2nd (list index starts from 0).

1.

List<Employee> sortedList = employeeList.stream()
.sorted(Comparator.comparingDouble(Employee::getSalary).reversed()).collect(Collectors.toList());

2. sortedList.get(1)