How to find if it's 32 or 64 bits? Tomcat

Question

I recently downloaded Tomcat 7.x as a zip. Running the version.bat gives the following:

c:\apache-tomcat-7.0.19\bin>version
Using CATALINA_BASE:   "C:\apache-tomcat-7.0.19"
Using CATALINA_HOME:   "c:\apache-tomcat-7.0.19"
Using CATALINA_TMPDIR: "C:\apache-tomcat-7.0.19\temp"
Using JRE_HOME:        "C:\Program Files (x86)\Java\jdk1.6.0_29"
Using CLASSPATH:       "c:\apache-tomcat-7.0.19\bin\bootstrap.jar;C:\apache-tomcat-    7.0.19\bin\tomcat-juli.jar"
Server version: Apache Tomcat/7.0.19
Server built:   Jul 13 2011 11:32:28
Server number:  7.0.19.0
OS Name:        Windows Server 2008 R2
OS Version:     6.1
Architecture:   x86
JVM Version:    1.6.0_29-b11
JVM Vendor:     Sun Microsystems Inc.

Since it's using the 32 bit version of JRE, is it a safe assumption the Tomcat itself is 32-bit?

Answer 1

In the Tomcat bin folder, there is version.bat (version.sh for linux) script. Run it to get version and architecture information. Here is example output for Tomcat 7.062 running 32 bit (x86) on Windows:

C:\KBData\Software\apache-tomcat-7.0.62\bin>version
Using CATALINA_BASE:   "C:\KBData\Software\apache-tomcat-7.0.62"
Using CATALINA_HOME:   "C:\KBData\Software\apache-tomcat-7.0.62"
Using CATALINA_TMPDIR: "C:\KBData\Software\apache-tomcat-7.0.62\temp"
Using JRE_HOME:        "C:\Program Files (x86)\Java\jdk1.7.0_25\"
Using CLASSPATH:       "C:\KBData\Software\apache-tomcat-7.0.62\bin\bootstrap.ja
r;C:\KBData\Software\apache-tomcat-7.0.62\bin\tomcat-juli.jar"
Server version: Apache Tomcat/7.0.62
Server built:   May 7 2015 17:14:55 UTC
Server number:  7.0.62.0
OS Name:        Windows 7
OS Version:     6.1
Architecture:   x86
JVM Version:    1.7.0_25-b17
JVM Vendor:     Oracle Corporation