How to execute multiple ClientScript.RegisterStartupScript in ASP.NET c#?

Question

I'm developing a gridview in which you can download multiple files with one button.

Here's my gridview:

<asp:GridView ID="grdvHistorialMensajes" runat="server" AllowPaging="True" 
                    AutoGenerateColumns="False" CellPadding="4" AllowSorting="true"
                    EmptyDataText="No Hay Mensajes Enviados" ForeColor="#333333" 
                    GridLines="None" CellSpacing="1" 
                    onpageindexchanging="grdvHistorialMensajes_PageIndexChanging" 
                    onrowcommand="grdvHistorialMensajes_RowCommand" 
                    onsorting="grdvHistorialMensajes_Sorting">
                    <AlternatingRowStyle BackColor="White" ForeColor="#284775" />

                    <Columns>
                        <asp:BoundField DataField="CorreoCliente" HeaderText="Correo Del Cliente" SortExpression="CorreoCliente" />
                        <asp:BoundField DataField="CorreosAdicionales" HeaderText="Correos Adicionales" SortExpression="CorreosAdicionales" />
                        <asp:BoundField DataField="Tema" HeaderText="Tema" SortExpression="Tema" />
                        <asp:BoundField DataField="Mensaje" HeaderText="Mensaje" SortExpression="Mensaje" />

                        <asp:TemplateField HeaderText="Fecha" SortExpression="Fecha">
                            <ItemTemplate>
                                <%# DataBinder.Eval(Container.DataItem, "Fecha", "{0:dd/MM/yyyy}")%>
                            </ItemTemplate>

                            <EditItemTemplate>
                                <asp:TextBox ID="tbxFecha" runat="server" Text='<%#Bind("Fecha","{0:dd/MM/yyyy}") %>' ValidationGroup="gpEdicionAgenda">
                                </asp:TextBox>
                            </EditItemTemplate>
                        </asp:TemplateField>

                        <asp:BoundField DataField="Hora" HeaderText="Hora" SortExpression="Hora" />
                        <asp:BoundField DataField="Archivos" HeaderText="Archivos" SortExpression="Archivos" />

                        <asp:TemplateField>
                            <ItemTemplate>
                                <asp:ImageButton ID="imgBtnDescargarArchivos" runat="server" 
                                    CommandArgument='<%# Eval("IdMensaje")%>' CommandName="Descargar" Height="16px" 
                                    ImageUrl="~/img/activar.png" ToolTip="Descargar" Width="16px" />
                            </ItemTemplate>
                        </asp:TemplateField>

                        <asp:TemplateField>
                            <ItemTemplate>
                                <asp:ImageButton ID="imgBtnVerMas" runat="server" 
                                    CommandArgument='<%# Eval("IdMensaje")%>' CommandName="VerMas" Height="16px" 
                                    ImageUrl="~/img/search.png" ToolTip="Ver Mas" Width="16px" />
                            </ItemTemplate>
                        </asp:TemplateField>
                    </Columns>

                    <EditRowStyle BackColor="#999999" />
                    <FooterStyle BackColor="#5D7B9D" Font-Bold="True" ForeColor="White" />
                    <HeaderStyle BackColor="#5D7B9D" Font-Bold="True" ForeColor="White" />
                    <PagerStyle BackColor="#284775" ForeColor="White" HorizontalAlign="Center" />
                    <RowStyle BackColor="#F7F6F3" ForeColor="#333333" HorizontalAlign="Center" />
                    <SelectedRowStyle BackColor="#E2DED6" Font-Bold="True" ForeColor="#333333" />
                    <SortedAscendingCellStyle BackColor="#E9E7E2" />
                    <SortedAscendingHeaderStyle BackColor="#506C8C" />
                    <SortedDescendingCellStyle BackColor="#FFFDF8" />
                    <SortedDescendingHeaderStyle BackColor="#6F8DAE" />
                </asp:GridView>

Whenever I click on the "Descargar" RowCommand, I originally used this:

if (e.CommandName == "Descargar")
            {
                DataTable dt = ConexionBD.GetInstanciaConexionBD().GetArchivosPorMensaje(Convert.ToInt32(e.CommandArgument));

                foreach (DataRow dr in dt.Rows)
                {
                    string strArchivo = dr["Nombre"].ToString();
                    string strExtension = Path.GetExtension(strArchivo).ToLower();
                    Response.Write("<script>window.open('/Archivos/" + strArchivo + "');</script>");
                }
            }

When I clicked, if that row had let's say 1 pdf, 1 jpg and 1 doc, it opened both the pdf and the jpg in a different window and the doc would be downloaded. That's exactly what I want. However, I noticed that whenever a new page is opened (in the case of the pdf and jpg) all the font in the page is altered. So I wanted to find a solution and then I tried this:

if (e.CommandName == "Descargar")
            {
                DataTable dt = ConexionBD.GetInstanciaConexionBD().GetArchivosPorMensaje(Convert.ToInt32(e.CommandArgument));

                foreach (DataRow dr in dt.Rows)
                {
                    string strArchivo = dr["Nombre"].ToString();
                    string strExtension = Path.GetExtension(strArchivo).ToLower();
                    ClientScript.RegisterStartupScript(this.GetType(), "myFileOpenScript", "<script>window.open('/Archivos/" + strArchivo + "');</script>");
                }
            }

When I open a pdf file, the font is not altered this time, however, It would only open/download the first file that appears int dt.Rows[0] (dt.Rows[1] on won't open). I suppose that a Response.Write can be deployed multiple times, however, a ClientScript.RegisterStartupScript probably can only be executed once.

Is there another method I can use to not alter the page's letter font and to open multiple files with a single click?

Or how could I execute ClientScript.RegisterStartupScript multiple times??

Thanks In Advance

Answer 1

A little extra information information would be helpful. You aren't limited from using RegisterStatupScript more than once, but you are limited from registering the same type/key combination more than once (this is a feature, not a limitation).

If you need to register different scripts, use a unique key. If you are simply doing a postback, re-registering the startup script will/should work.

http://msdn.microsoft.com/en-us/library/system.web.ui.clientscriptmanager.aspx

Answer 2

ClientScript.RegisterStartupScript(this.GetType(),
    "myFileOpenScript",
    "<script>window.open('/Archivos/" + strArchivo + "');</script>");

The script key here is myFileOpenScript.

A client script is uniquely identified by its key and its type. Scripts with the same key and type are considered duplicates. Only one script with a given type and key pair can be registered with the page. Attempting to register a script that is already registered does not create a duplicate of the script. http://msdn.microsoft.com/en-us/library/asz8zsxy.aspx

You can use Guid.NewGuid() to generate a different key each time. And you would probably want to use

RegisterStartupScript(Type, String, String, Boolean)

instead. The last parameter (boolean) tells it to create the script tags for you, so the script parameter can contain only your code not worrying about the tags.