#Example Script
wget http://file1.com
cd /dir
wget http://file2.com
wget http://file3.com
I want to execute the bash script line by line and test the exit code ($?) of each execution and determine whether to proceed or not:
It basically means I need to add the following script below every line in the original script:
if test $? -eq 0
then
echo "No error"
else
echo "ERROR"
exit
fi
and the original script becomes:
#Example Script
wget http://file1.com
if test $? -eq 0
then
echo "No error"
else
echo "ERROR"
exit
fi
cd /dir
if test $? -eq 0
then
echo "No error"
else
echo "ERROR"
exit
fi
wget http://file2.com
if test $? -eq 0
then
echo "No error"
else
echo "ERROR"
exit
fi
wget http://file3.com
if test $? -eq 0
then
echo "No error"
else
echo "ERROR"
exit
fi
But the script becomes bloated.
Is there a better method?
One can use set -e but it's not without it's own pitfalls. Alternative one can bail out on errors:
command || exit 1
And an your if-statement can be written less verbose:
if command; then
The above is the same as:
command
if test "$?" -eq 0; then
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