how to create an array of Bitset in c++

Question

I want to create an array of Bitset .Binary Bitset(example "100","1010",etc) After that I want to input from user and store in the the Bitset . I have tried the following line but it says error.

#include<bits/stdc++> 
using namespace std;
int main() 
{ 
  int n,i;
  string bit_string; 
  cin>>n  // size of Bitset array.
  bitset<8> brr[n];//  
  for(i=0;i<n;i++)
  {
    cin>>bit_string;
    brr[i](bit_string);
  }



  return 0; 
}  

I want to create n Bitset each of size 8 bits.Where n is given by user. my input is binary string like. "110010","001110" please help

Answer 1

The error ocurrs because you are trying to creat a C-style array using n which is not compile-time constant. It's not possible to creat a C-style array without being n known at compile time.

The following is a good way to do what you want

Creat a std::vector<std::bitset<8>> to hold your bitset<8>s, as follows.

Note that the code ignores the excess of characters in strings iput like "111111110" (makes it "11111111") and treats any character except '1' as if it were '0' and if the input string is less than 8 characters, the code adds zeros by the default of the bitsets

#include <vector>
#include <bitset>
#include <iostream>
int main() {
    int n, i;
    std::string bit_string;
    std::cout << "Enter the size";
    std::cin >> n; // size of Bitset array.
    std::vector<std::bitset<8>> brr(n);//
    for (i = 0; i < n; i++) {
        std::cin >> bit_string;
        for (int j{}; j < bit_string.size() && j < 8; ++j) {
            brr[i][j] = (bit_string[j] == '1') ? 1 : 0;
        }
    }
    //To test

    for(auto const& el :brr)
    {
        for(int i{}; i < 8;)
            std::cout << el[i++];
        std::cout<<"\n";
    }
}

See Why is "using namespace std;" considered bad practice? and Why should I not #include <bits/stdc++.h>?