Say I have an array of 3 integers. I want to be able to obtain these results from these arrays using just if statements or a for loop.
[0,1,2] = 0 equal
[0,1,0] = 2 equal
[0,0,0] = 3 equal
This what i have so far and it works, but I think it could be simplified.
int numequal = 0;
if(intarr[0] != null && intarr[1] != null && intarr[0].numequals(intarr[1])) {
numequal++;
}
if(intarr[0] != null && intarr[2] != null && intarr[0].numequals(intarr[2])) {
numequal++;
}
if(intarr[1] != null && intarr[2] != null && intarr[1].numequals(intarr[2])) {
numequal++;
}
if(numequal == 1) {
numequal = 2;
}
Also, I'm trying to keep it basic. Maybe just for loops. No hash sets or dictionaries.
You are probably looking for really simple solution so I tried to optimize your code a bit:
int[] intarr = {'0','1','2'};
int numequal = 0;
if(intarr[0] == intarr[1] || intarr[0] == intarr[2] ){
numequal++;
}
if( intarr[1] == intarr[2]){
numequal++;
}
if (numequal > 0 ){
numequal++;
}
if your array is declared as int[] there is no need to check for nulls
intarr[1] != null.
If some item is not set, it will be default 0
Here is my solution. It is not simple but very efficient. Currently it counts null elements too, which can easily be fixed if it's undesirable.
Integer[] a = { null, 2, 1, null, 0, 1 };
Arrays.sort(a, new Comparator<Integer>() {
@Override
public int compare(Integer o1, Integer o2) {
if (o1 == null) {
return -1;
}
if (o2 == null) {
return 1;
}
return o1.compareTo(o2);
}
});
// [null, null, 0, 1, 1, 2]
int n = 0;
Integer prev = null;
Boolean first = null;
for (Integer e : a) {
if (first != null && (e == prev || e != null && e.equals(prev))) {
if (first == Boolean.TRUE) {
n += 2;
first = Boolean.FALSE;
} else {
n++;
}
} else {
first = Boolean.TRUE;
}
prev = e;
}
System.out.println(n);
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