I want/need to create a matrix of 1's and 0's that contains the information about common terms. I created a matrix of common terms between columns (e.g. with rows like 1,4,2) but I do not figure out how to disaggregate it.
Here is a toy and reproducible example. Steps (1)-(4) are ok and step (5) is what I cannot do at the moment.
(1) I have this (fictional) dataset
vec1 <- c("apple","pear","apple and pear")
vec2 <- c("apple and pear","banana","orange")
vec3 <- c("orange and pear","banana","apple")
my.data.frame <- as.data.frame(cbind(vec1,vec2,vec3))
vec1 vec2 vec3
1 apple apple and pear orange and pear
2 pear banana banana
3 apple and pear orange apple
(2) I extract the variables and the content
vectors.list <- as.vector(colnames(my.data.frame))
list.of.fruits <- unique(as.vector(unlist(my.data.frame)))
(2) I write down a function to count common terms (this is a deformation of this post: How to count common words and store the result in a matrix?)
common.fruits <- function(vList) {
v <- lapply(vList, tolower)
do.call(rbind, lapply(v, function(x) {
do.call(c, lapply(v, function(y) length(intersect(x, y))))
}))
}
(4) I use get and lapply to do some efficient (I guess) calculation
compare <- lapply(vectors.list,get)
common.terms.matrix <- common.fruits(compare)
rownames(common.terms.matrix) <- vectors.list
colnames(common.terms.matrix) <- vectors.list
common.terms.matrix
vec1 vec2 vec3
vec1 3 1 1
vec2 1 3 1
vec3 1 1 3
(5) How do I disaggregate that last matrix into this matrix or data.frame (the "|" are to indicate that this was written by hand)
| apple | pear | apple and pear | banana | orange | orange and pear
vec1 | 1 | 1 | 1 | 0 | 0 | 0
vec2 | 0 | 0 | 1 | 1 | 1 | 0
vec3 | 1 | 0 | 0 | 1 | 0 | 1
You can try
table(col(my.data.frame), as.matrix(my.data.frame))
apple apple and pear banana orange orange and pear pear
1 1 1 0 0 0 1
2 0 1 1 1 0 0
3 1 0 1 0 1 0
Then you can order the output using sort or so.
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