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How to convert dateutil.relativedelta object to datetime.timedelta object?

How can I convert a dateutil.relativedelta object to a datetime.timedelta object?

e.g.,

# pip install python-dateutil

from dateutil.relativedelta import relativedelta
from datetime import timedelta

rel_delta = relativedelta(months=-2)
# How can I convert rel_delta to a timedelta object so that I can call total_seconds() ?
time_delta = ???(rel_delta)  
time_delta.total_seconds()  # call the timedelta.total_seconds() method
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Rob Bednark Avatar asked Oct 25 '25 06:10

Rob Bednark


2 Answers

You can't, for one huge reason: They don't store the same information. datetime.timedelta only stores days, seconds, and milliseconds, whereas dateutil.relativedelta stores every single time component fed to it.

That dateutil.relativedelta does so is important for storing things such as a difference of 1 month, but since the length of a month can vary this means that there is no way at all to express the same thing in datetime.timedelta.

like image 84
Ignacio Vazquez-Abrams Avatar answered Oct 26 '25 19:10

Ignacio Vazquez-Abrams


In case someone is looking to convert a relativedelta to a timedelta from a specific date, simply add and subtract the known time:

utcnow = datetime.utcnow()
rel_delta = relativedelta(months=-2)
time_delta = utcnow + rel_delta - utcnow  # e.g, datetime.timedelta(days=-62)

As a commenter points out, the resulting timedelta value will differ based on what month it is.

like image 27
Ben Avatar answered Oct 26 '25 18:10

Ben