How is the ordering of std::map achieved?

Question

We can see from several sources that std::map is implemented using a red-black tree. It is my understanding that these types of data structures do not hold their elements in any particular order and just maintain the BST property and the height balancing requirements.

So, how is it that map::begin is constant time, and we are able to iterate over an ordered sequence?

Answer 1

Starting from the premise that std::map is maintaining a BST internally (which is not strictly required by the standard, but most libraries probably do that, like a red-black tree).

In a BST, to find the smallest element, you would just follow the left branches until you reach a leaf, which is O(log(N)). However, if you want to deliver the "begin()" iterator in constant time, it is quite simple to just keep track, internally, of the smallest element. Every time an insertion causes the smallest element to change, you update it, that's all. It's memory overhead, of course, but that's a trade-off.

There are possibly other ways to single out the smallest element (like keeping the root node unbalanced on purpose). Either way, it's not hard to do.

To iterate through the "ordered" sequence, you simply have to do an in-order traversal of the tree. Starting from the left-most leaf node, you go (up), (right), (up, up), (right), ... so on.. it's a simple set of rules and it's easy to implement, just see a quick implementation of a simple BST inorder iterator that I wrote a while back. As you do the in-order traversal, you will visit every node from the smallest to the biggest, in the correct order. In other words, it just gives you the illusion that "array" is sorted, but in reality, it's the traversal that makes it look like it's sorted.