I already have a list of data frames (mylist) and need to switch the first and second column for all the data frames in the list.
[reads] [phylum]
1 phylum1
2 phylum2
3 phylum3
Into....
[phylum] [reads]
phylum1 1
phylum2 2
phylum3 3
I know I need to use lapply, but not sure what to input for the FUN=
mylist <- lapply(mylist, FUN = mylist[ ,c("phylum", "reads")])
errors saying incorrect number of dimensions
Sorry if this is a simple question and thanks in advance for your help!
-Brand new R user
The FUN asks for a function that it can apply to every element in the list. You are passing mylist[ ,c("phylum", "reads")]) which is not a function.
# sample data
df1 <- data.frame(reads = sample(10,4), phylum = sample(10,4))
df2 <- data.frame(reads = sample(10,4), phylum = sample(10,4))
df3 <- data.frame(reads = sample(10,4), phylum = sample(10,4))
df4 <- data.frame(reads = sample(10,4), phylum = sample(10,4))
ldf <- list(df1,df2,df3,df4)
ldf_re <- lapply(ldf, FUN = function(X){X[c('phylum', 'reads')]})
In the last line, the lapply will iterate through all the dataframes, they will be passed as the X argument for the function defined in the FUN argument and the columns will be dataframes will be stored in the list ldf_re with their columns rearranged.
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