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I have some code that'll allow me to open up a random website from a list of websites but I'd like to open each one up in a new tab, how do I do this?
the code
<html>
<button onclick="randomLink();OpenInNewTab();">Click here to go somewhere else! </button>
<script type="text/javascript">
var randomLink = function () {
// first create an array of links
var links = [
"bbc.com",
"google.com",
"youtube.com",
"facebook.com"
];
// then work out the maximum random number size
// by counting the number of links in the array
var max = (links.length)
// now generate a random number
var randomNumber = Math.floor(Math.random()*max);
// use that random number to retrieve a link from the array
var link = links[randomNumber];
// change the location of the window object
window.location = "http://" + link;
// Opens a new tab.
function OpenInNewTab(url) {
var win = window.open(url, '_blank');
win.focus();
}
}
</script>
</html>
I tried doing the action in question at two different points and hope you're input can help to correct this.
Location 1
<button onclick="randomLink();OpenInNewTab();">Click here to go somewhere else!
Location 2
// Opens a new tab.
function OpenInNewTab(url) {
var win = window.open(url, '_blank');
win.focus();
The following web address is what the code currently looks like and does.
*EDIT : The only changes I made are the websites.They're much more on the live demo.
485
asked Dec 07 '25 23:12
The code you wrote is wrong, since you change the address of the current window (via the line window.location=..., and other issues... but here:
Very similar, and works.
<button onclick="openStuff();">Click here to go somewhere else!</button>
// the used links
var links = [
"bbc.com",
"google.com",
"youtube.com",
"facebook.com"];
openStuff = function () {
// get a random number between 0 and the number of links
var randIdx = Math.random() * links.length;
// round it, so it can be used as array index
randIdx = parseInt(randIdx, 10);
// construct the link to be opened
var link = 'http://' + links[randIdx];
// open it in a new window / tab (depends on browser setting)
window.open(link);
};
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