I just learnt about Enums and Types in Ada and decided to write a small program to practice:
with Ada.Text_IO;                       use Ada.Text_IO;
with Ada.Integer_Text_IO;       use Ada.Integer_Text_IO;
procedure Day is 
    type Day_Of_The_Week is (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday);
    subtype Weekday is Day_Of_The_Week range Monday..Friday;
    subtype Weekend is Day_Of_The_Week range Saturday..Sunday;
        function is_Weekday ( dayOfTheWeek: in Day_Of_The_Week) return Boolean is
        begin
            if(--?--)
        end is_Weekday;
    selected_day_value  :   Integer;
    selected_day                :   Day_Of_The_Week;
begin
    Put_Line("Enter the number co-responding to the desired day of the week:");
    Put_Line("0 - Monday");
    Put_Line("1 - Tuesday");
    Put_Line("2 - Wednesday");
    Put_Line("3 - Thursday");
    Put_Line("4 - Friday");
    Put_Line("5 - Saturday");
    Put_Line("6 - Sunday");
    Get(selected_day_value);
    selected_day = Day_Of_The_Week'pos(selected_day_value);
    if( is_Weekday(selected_day))
        Put_Line( Day_Of_The_Week'Image(selected_day) & " is a weekday." );
    else
        Put_Line( Day_Of_The_Week'Image(selected_day) & " is a weekday." );
end Day;
I'm having trouble with the if statement. How can I check whether or not dayOfTheWeek is in the Weekday subtype or the weekend subtype?
You want
function is_Weekday ( dayOfTheWeek: in Day_Of_The_Week) return Boolean is
begin
    return dayoFTheWeek in Weekday;
end is_Weekday;
Also, you want ’Val not ’Pos in
selected_day := Day_Of_The_Week'val(selected_day_value);
and you might take a look at the words in the second Put_Line!
You don't need a function to check for this. In this case a function only obscures what happens:
if Selected_Day in Weekday then
  do stuff..
else
  do other stuff...
end if;
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With