How can i give the external link to UIButton?Is it possible?

Question

I am having the UIButton name as "Buy now".If any one touch the button,the external link should open in the safari browser.How can i achieve this?

Answer 1

It's easy. You set the target and selector for the button, then inside the selector, you call safari to open your link.

Code to call Safari:

Objective-C

- (void)buttonPressed {
    [[UIApplication sharedApplication] 
        openURL:[NSURL URLWithString: @"https://www.google.co.uk"]];
}

Swift 2.x

UIApplication.sharedApplication().openURL(NSURL(string: "https://www.google.co.uk")!)

Swift 3.x

UIApplication.shared.openURL(URL(string: "https://www.google.co.uk")!)

Answer 2

Create a button, and give it a target to a selector that opens Safari with the link.

Basic example:

Make a UIButton

UIButton *button = [[UIButton alloc] initWithFrame:...];
[button addTarget:self action:@selector(someMethod) forControlEvents:UIControlEventTouchUpInside];

Then the method to open the URL

-(void)someMethod {
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString: @"http://www.google.ca"]];
}

Don't forget to give your button a proper frame and title, and to add it to your view.