Here's the code I'm using :
public class splitText {
public static void main(String[] args) {
String x = "I lost my Phone. I shouldn't drive home alone";
String[] result = x.split(".");
for (String i : result) {
System.out.println(i);
}
}
}
Compiles perfectly, but nothing happens at runtime. What am I doing wrong?
String.split(String regex) takes a regular-expression pattern. It just so happens that . in regex is a metacharacter that matches (almost) any character, hence why split(".") doesn't work the way you expected.
You can escape the . by preceding it with a backslash. As a Java string literal, this is "\\.". The \ is doubled because \ itself is a Java escape character. "\\." is a String of length 2, containing a backslash and a period.
If you're given an arbitrary String that is to be matched literally (or if you just don't care to escape them yourself), you can use Pattern.quote. It'll make a pattern to literally match a given String.
This is provided for educational purposes only:
String text =
"Wait a minute... what?!? Oh yeah! This is awesome!!";
for (String part : text.split("(?<=[.?!]) ")) {
System.out.println(part);
}
This prints:
Wait a minute...
what?!?
Oh yeah!
This is awesome!!
(?<=#)[^#]+(?=#) work?String.split uses a regex, so dot (.) means "anything". You need to escape the dot
public static void main(String[] args) {
String x = "I lost my Phone. I shouldn't drive home alone";
String[] result = x.split("\\.");
for (String i : result) {
System.out.println(i.trim());
}
}
gives :
I lost my Phone
I shouldn't drive home alone
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