Groovy execute a git shell command

Question

I'm trying to execute git shell command in groovy. The first is executed well but the second returns the exit code 128:

   def workingDir = new File("path/to/dir")
   "git add .".execute(null, workingDir)
   def p = "git reset --hard".execute( null, workingDir )
   p.text.eachLine {println it}
   println p.exitValue()

what's the problem with this code?

Answer 1

The second process is starting before the first one completes. When the second git process starts git recognizes that there is already a git process operating in that same directory which could cause problems so it errors out. If you read the error stream from the first process you will see something like this:

fatal: Unable to create 'path/to/dir/.git/index.lock': File exists.

If no other git process is currently running, this probably means a
git process crashed in this repository earlier. Make sure no other git
process is running and remove the file manually to continue.

If you wait for the first one to finish before starting the second one, that should work. Something like this:

def workingDir = new File("path/to/dir/")

def p = "git add .".execute(null, workingDir)
p.waitFor()
p = "git reset --hard".execute( null, workingDir )
p.text.eachLine {println it}
println p.exitValue()