I am trying to Deserialize a json using fasterxml jackson , one of the fields in Json is a string but i need to read the same in a byte array PFB the Bean and main class
public class Serialization implements Serializable{
private static final long serialVersionUID = 5894318390213780082L;
private String name = null;
@JsonDeserialize(using = StringtoByteArray.class)
private byte[] pass = null;
//getter setter
}
public class StringtoByteArray extends JsonDeserializer<byte []> {
@Override
public byte[] deserialize(JsonParser jsonParser, DeserializationContext deserializationContext)
throws IOException, JsonProcessingException {
return (jsonParser.getBinaryValue());
}
}
public class App
{
public static void main(String[] args) throws JsonGenerationException, JsonMappingException, IOException {
Serialization sr = new Serialization();
ObjectMapper mapper = new ObjectMapper();
sr = mapper.readValue(new File("D:\\check.json"), Serialization.class);
System.out.println("sr values ::" +sr.toString());
mapper.writeValue(new File("c:\\user.json"), sr);
}
}
My json
{
"name": "AD",
"pass": "pp"
}
At the time of Deserialize getting Exception in thread "main" com.fasterxml.jackson.databind.JsonMappingException: Failed to decode VALUE_STRING as base64 (MIME-NO-LINEFEEDS): Illegal character '"' (code 0x22) in base64 content Kindly suggest
If using Java 8 : In my Deserialize implementation i needed to return
return (Base64.getEncoder().encode(jsonParser.getText().getBytes()))
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