Extract ZipArchive entry to blob storage

Question

Using the normal Windows file system, the ExtractToFile method would be sufficient:

using (ZipArchive archive = new ZipArchive(uploadedFile.InputStream, ZipArchiveMode.Read, true))
{
    foreach (var entry in archive.Entries.Where(x => x.Length > 0))
    {
        entry.ExtractToFile(Path.Combine(location, entry.Name));
    }
}

Now that we are using Azure, this obviously needs to change as we are using blob storage.

How can this be done?

Answer 1

ZipArchiveEntry class has an Open method which returns a stream. What you could do is create a blob using that stream.

static void ZipArchiveTest()
        {
            storageAccount = CloudStorageAccount.DevelopmentStorageAccount;
            CloudBlobContainer container = storageAccount.CreateCloudBlobClient().GetContainerReference("temp");
            container.CreateIfNotExists();
            var zipFile = @"D:\node\test2.zip";
            using (FileStream fs = new FileStream(zipFile, FileMode.Open))
            {
                using (ZipArchive archive = new ZipArchive(fs))
                {
                    var entries = archive.Entries;
                    foreach (var entry in entries)
                    {
                        CloudBlockBlob blob = container.GetBlockBlobReference(entry.FullName);
                        using (var stream = entry.Open())
                        {
                            blob.UploadFromStream(stream);
                        }
                    }
                }
            }
        }