Executing a Dummy Statement

Question

In my current program I have a function already defined as

void functionName( const customClass object );

Now, in the code for this function, this object is not used. I don't have permission to to remove the parameter, nor can I remove the unused parameter warning.

Is there a statement I can execute with this object (customClass doesn't have any functions which I can run here), so that this warning doesn't happen?

Answer 1

You can remove the name of the parameter from the definition:

void functionName( const customClass );

This doesn't change the signature of the function (it's compatible with your existing declaration), but since the variable isn't named there won't be an unused parameter warning.

Answer 2

Common way to do this is

void functionName(const customClass object)
{
    (void)object; // gets rid of warning
}