Echo missing after generating image

Question

$data = 'iVBORw0KGgoAAAANSUhEUgAAABwAAAASCAMAAAB/2U7WAAAABl'
      . 'BMVEUAAAD///+l2Z/dAAAASUlEQVR4XqWQUQoAIAxC2/0vXZDr'
      . 'EX4IJTRkb7lobNUStXsB0jIXIAMSsQnWlsV+wULF4Avk9fLq2r'
      . '8a5HSE35Q3eO2XP1A1wQkZSgETvDtKdQAAAABJRU5ErkJggg==';
$data = base64_decode($data);

$im = imagecreatefromstring($data);
if ($im !== false) {

    header("Cache-Control: no-cache, must-revalidate");
    header("Expires: Mon, 26 Jul 1997 05:00:00 GMT");
    header('Content-Type: image/png');
    imagepng($im);

    //echo '<a href=\'imagepng('.$im.')\'> Download </a>';
    echo "-----------------";

} else {
    echo 'An error occurred.';
}

It shows the image but does not echo "==============".

Answer 1

You told the browser to expect an image, therefore it's only expecting an image. Everything sent will be considered part of the data for that image. And no, it won't convert text you send into part of the image.

Answer 2

This is because of your

header('Content-Type: image/png');

It prevents you from echoing something else than the picture on this page. (Well it doens't, but your Browser thinks this still part of the picture)

If you want to echo picture and Text, you need a seperat file, e.g. like this

echo '<img source="./pic.php" alt="pic" height="20" width="20" />';
echo '______________';

wehere pic.php is the path to the file wich echos the picture.