I wanna register a user using Spring MVC 3, Hibernate, and PostgresQL. Here Is the form I wanna submit:
<form:form name="registerForm" method="post"
action="registerNewUser.html" commandName="user">
<table>
<tr>
<td><spring:message code="label.userName" /></td>
<td><form:input path="userName" /></td>
<td><form:errors path="userName" cssClass="error" /></td>
</tr>
<tr>
<td><spring:message code="label.password" /></td>
<td><form:password path="password" /></td>
<td><form:errors path="password" cssClass="error" /></td>
</tr>
<tr>
<td><spring:message code="label.password" /></td>
<td><form:password path="retypePassword" /></td>
<td><form:errors path="retypePassword" cssClass="error" /></td>
</tr>
<tr>
<td colspan="2"><input type="submit"
value="<spring:message code="register.label" />" /></td>
</tr>
</table>
</form:form>
here is the POJO I want to save:
@Entity
@Table(name = "user_table")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column(name = "user_name", nullable = false, length = 50)
private String userName;
@Column(name = "password", nullable = false, length = 50)
private String password;
private String retypePassword;
// getters setters
and here is the relevant part of the Controller:
@RequestMapping(value = "/registerNewUser", method = RequestMethod.POST)
public String saveNewUser(@ModelAttribute User user, BindingResult result, Model model, HttpSession session) {
UserValidator validator = new UserValidator();
validator.validateUser(user, result, userService.existingUser(user));
String ret = REGISTER_USER;
if (!result.hasErrors()) {
user.setPassword(PasswordEncripter.md5(user.getPassword()));
userService.save(user);
ret = goToPractice(user, model, session);
}
return ret;
}
Because I feel it wasteful to store the value of retypePassword in the DB I did not create a column for that. That caused the exception below when I submitted the form:
org.postgresql.util.PSQLException: ERROR: column user0_.retypepassword does not exist
I could easily fix this exception by adding the column "retypePassword" to the table but I still feel that would be wasteful. Is there any clever way to fix the problem without adding duplicate data in the DB?
You can mark retypePassword in entity with @Transient
, this will instruct hibernate not to create column in table but still you can use this pojo to bind with spring mvc for validation purpose.
@Entity
@Table(name = "user_table")
public class User {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column(name = "user_name", nullable = false, length = 50)
private String userName;
@Column(name = "password", nullable = false, length = 50)
private String password;
@Transient
private String retypePassword;
// getters setters
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