Why static_cast cannot downcast from a virtual base ?
struct A {}; struct B : public virtual A {}; struct C : public virtual A {}; struct D : public B, public C {}; int main() { D d; A& a = d; D* p = static_cast<D*>(&a); //error } g++ 4.5 says:
error: cannot convert from base ‘A’ to derived type ‘D’ via virtual base ‘A’ The solution is to use dynamic_cast ? but why. What is the rational ?
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Very good answers below. No answers detail exactly how sub objects and vtables end up to be ordered though. The following article gives some good examples for gcc:
http://www.phpcompiler.org/articles/virtualinheritance.html#Downcasting
The obvious answer is: because the standard says so. The motivation behind this in the standard is that static_cast should be close to trivial—at most, a simple addition or subtraction of a constant to the pointer. Where s the downcast to a virtual base would require more complicated code: perhaps even with an additional entry in the vtable somewhere. (It requires something more than constants, since the position of D relative to A may change if there is further derivation.) The conversion is obviously doable, since when you call a virtual function on an A*, and the function is implemented in D, the compiler must do it, but the additional overhead was considered inappropriate for static_cast. (Presumably, the only reason for using static_cast in such cases is optimization, since dynamic_cast is normally the preferred solution. So when static_cast is likely to be as expensive as dynamic_cast anyway, why support it.)
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