Disambiguate nested class and member function with same name in template

Question

See the example: compilable here

// Example program
#include <iostream>
#include <string>

class Foo {
    public:
    
    class Nes{};

    void Nes(){}

    using Ptr = void(Nes::*)();
 };

 template<typename T> class Bar
 {
 public:

     using Ptr = void(T::Nes::*)();
 };

int main()
{
    using F = void(Foo::Nes::*)();
    F compiles;

    Bar<Foo>::Ptr notCompiles;

    std::cout << typeid(Foo).name();
}

How can tell to the compiler that Nes should be the class and not the method?

Answer 1

In this case:

template<typename T> class Bar {
public:
    using Ptr = typename T::Ptr;
};

If T doesn't have a Ptr type definition:

template <typename T> class Bar {
public:
    using TNes = class T::Nes;
    using Ptr = void (TNes::*)();
};