could not find deserializer for type : Error

Question

I have to make a SOAP call from my java program ,for which I used apache axis. My program is as follows :

import org.apache.axis.client.Call;
import org.apache.axis.client.Service;
import javax.xml.rpc.ParameterMode;
import javax.xml.namespace.QName;
public class Project {
   public static void main(String [] args) {

   try {

       String endpoint ="http://RequestUrl";
       Service  service = new Service();
       Call call = (Call) service.createCall();
       call.setTargetEndpointAddress( new java.net.URL(endpoint) );
       call.setOperationName(new QName(endpoint, "getFrsFileData"));
       String value = (String) call.invoke(new Object[] { "24BB7","frs1001" } );
       System.out.println(value);
       }

    catch (Exception e) {
       System.err.println(e.toString());
       }

    }
   }

This on execution gives an error as follows

• Exception: org.xml.sax.SAXException: Deserializing parameter 'getFrsFileDataReturn': could not find deserializer for type {http://Url}FrsFileSoapDO at org.apache.axis.message.RPCHandler.onStartChild(RPCHandler.java:277) at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035) at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165) at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141) at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345) at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384) at org.apache.axis.client.Call.invoke(Call.java:2467) at org.apache.axis.client.Call.invoke(Call.java:2366) at org.apache.axis.client.Call.invoke(Call.java:1812) at Project.main(Project.java:33) org.xml.sax.SAXException: Deserializing parameter 'getFrsFileDataReturn': could not find deserializer for type {http://Url}FrsFileSoapDO

Tried the same call using SOAPUI , but it did not help me debug this .

Please help me out in debugging this java code,

Thank You

Answer 1

I got help from my friend and was able to arrive at the answer . The problem is that the soap call , gives a soap response which comes as a bean of type "FrsFileSoapDO" . As I have not given anything in code of how my program will understand the received bean , that gave me an error saying "could not find deserializer for type {http://Url}FrsFileSoapDO" . Now the step's to clear the problem is

1) create a "QName" to say what is the namespace that "FrsFileSoapDO" refers to .

2) create Bean serializer (that knows how to serialize the bean),

3) create a Bean deserializer (that knows how to deserialize the bean) ,

4) Do the mapping saying that the QName q maps to the class FrsFileSoapDO.class (before that make sure that you have the FrsFileSoapDO.class with you and you have imported it )

Now lets implement this in the program , (I am repeating only the try block here)

try {

   String endpoint ="http://RequestUrl";
   Service  service = new Service();
   Call call = (Call) service.createCall();
   call.setTargetEndpointAddress( new java.net.URL(endpoint) );

   QName q = new QName ("http://Url", "FrsFileSoapDO"); // step 1
   BeanSerializerFactory bsf =   new BeanSerializerFactory(FrsFileSoapDO.class,q);   // step 2
   BeanDeserializerFactory bdf = new BeanDeserializerFactory(FrsFileSoapDO.class,q);  // step 3
   call.registerTypeMapping(FrsFileSoapDO.class,q, bsf, bdf); //step 4

   call.setOperationName(new QName(endpoint, "getFrsFileData"));
   FrsFileSoapDO s = (FrsFileSoapDO) call.invoke(new Object[] { "24BB7","frs1001" } );  
   System.out.println(s.getFilename());  
   }

This works giving me the expected output.

The document for the functions Call,BeanSerializerFactory,BeanDeserializerFactory are available at BeanSerializerFactory and BeanDeserializerFactory