Convert numpy array full of time deltas to hours

Question

I have a numpy array full of timedeltas I want to be able to convert them to hours.

print(times_arr)

array([datetime.timedelta(seconds=28800),
       datetime.timedelta(seconds=30600),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=27000),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=30600),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=27000),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=30600),
       datetime.timedelta(seconds=27000),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=23400),
       datetime.timedelta(seconds=30600),
       datetime.timedelta(seconds=28800),
       datetime.timedelta(seconds=23400)])

Does anyone know how I can convert this array to hours so array[(8, 8.56 etc..

I have tried everything I know how. I am new to python. Thanks

Answer 1

Convert to timedelta64[m] dtype, then go from there:

arr.astype('timedelta64[m]').astype(int) / 60
# array([8. , 8.5, 6.5, 7.5, 6.5, 6.5, 8.5, 6.5, 7.5, 6.5, 8.5, 7.5, 6.5,
#        6.5, 8.5, 8. , 6.5])

Answer 2

Use arr.astype('timedelta64[s]').astype("int64")/3600 instead of arr.astype('timedelta64[m]').astype(int) / 60 which will cause "loss" of seconds.