I am trying to assign a value to column 'Percentage' based on multiple columns 'Class' and 'Value'
Below is a link that has my dataframe: https://filebin.net/fo2wk7crmwf0fycc
This is the logic that I want to be applied:
If df['Class'] equals 2 or 3, and if df['Value'] is less than 0.5, set df['Percentage'] to 0
If df['Class'] equals 2 or 3, and if df['Value'] is > 0.5 and <= 0.7, set df['Percentage'] to 0.25
If df['Class'] equals 2 or 3, and if df['Value'] is > 0.7 and <= 0.9, set df['Percentage'] to 0.5
Else set df['Percentage'] to 1
Below is an example of the output I am looking for:
| Class | Value | Percentage |
|---|---|---|
| 2 | 0.01 | 0 |
| 2 | 0.6 | 0.25 |
| 3 | 0.9 | 0.5 |
| 3 | 3 | 1 |
Thank you
searchsortedWhen using searchsorted you don't need to include the boundaries like 0 and 1 in this case.
bins = np.array([.5, .7, .9])
labels = np.array([0, .25, .5, 1])
cut = bins.searchsorted(df.Value)
results = labels[cut]
df.assign(Percentage=np.where(df['Class'].isin([2, 3]), results, 1))
Class Value Percentage
0 2 0.000620 0.0
1 2 0.000620 0.0
2 3 0.001240 0.0
3 4 0.000620 1.0
4 5 0.000620 1.0
... ... ... ...
14782 5 0.001178 1.0
14783 2 0.001116 0.0
14784 3 0.001178 0.0
14785 5 0.000310 1.0
14786 5 0.001116 1.0
[14787 rows x 3 columns]
cutWhen using pd.cut you DO need the boundaries because Pandas will create intervals.
# / boundaries \
# ↓ ↓
cut = pd.cut(df.Value, [0, .5, .7, .9, 1], labels=[0, .25, .5, 1])
df.assign(Percentage=np.where(df['Class'].isin([2, 3]), cut, 1))
Class Value Percentage
0 2 0.000620 0.0
1 2 0.000620 0.0
2 3 0.001240 0.0
3 4 0.000620 1.0
4 5 0.000620 1.0
... ... ... ...
14782 5 0.001178 1.0
14783 2 0.001116 0.0
14784 3 0.001178 0.0
14785 5 0.000310 1.0
14786 5 0.001116 1.0
[14787 rows x 3 columns]
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