Combining logical operators in Ruby

Question

I am currently working through Ruby Koans and I am faced with a situation where I want to accomplish the following:

if ones > 2 || twos > 2 || threes > 2 || fours > 2 || fives > 2 || sixes > 2
    #do something
end

Is there a better way to code this if-statement?

Any help is much appreciated.

Answer 1

Do as below using Enumerable#any?:

if [ones,twos,threes,fours,fives,sixes].any?{|e| e > 2 }
   # do something
end

or as Jörg W Mittag suggested -

if [ones,twos,threes,fours,fives,sixes].any?(&2.method(:<))
   # do something
end

Answer 2

Using Enumerable#max:

ones, twos, threes, fours, fives, sixes = 1, 2, 3, 4, 5, 6
[ones, twos, threes, fours, fives, sixes].max > 2
# => true
[ones, twos, threes, fours, fives, sixes].max > 6
# => false

If the condition is more complex using Enumerable#any? is more preferable as Arup Rakshit's answer.