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So I am really new to C programming and trying to replace a string to a date from a file i read and then write it to an other file. But the problem is that when i write it into the file the string remains the same.
What I want is to read this from a file:
<html>
<head>
<!--#include file=”date”-->
</head>
<body>
</body>
</html>
Output file
<html>
<head>
Sat Nov 3 14:43:53 2012
</head>
<body>
</body>
</html>
I get an error: passing argument 1 in date_change from incompatible pointer type
Code
//System date replacement function
void *date_change(char** s, char* str, char* date){
static char buffer[4096];
char *p;
if(!(p = strstr(*s, str))) // <!--#echo var=\"date\"--> find this
return *s;
strncpy(buffer, *s, p-*s); //
buffer[p-*s] = '\0';
sprintf(buffer+(p-*s), "%s%s", date, p+strlen(str));
return buffer;
}
//main
int main(int argc, char *argv[]){
int f;
f = open(argv[1], O_RDONLY);
if(errno != 0){
perror("Hiba");
exit(1);
}
//read from file
char c[1000];
while(read(f,&c, 1000)){
}
// --------------------------------// Get the System date and trying to replace it with the date_change function
time_t mytime;
mytime = time(NULL);
struct tm *time = localtime(&mytime);
char date[20];
strftime(date, sizeof(date), "%c", time); //format time as string
char* date_str;
int g = open("data.txt", O_WRONLY | O_CREAT, 0600);
//should replace all <!--#echo var=\"date\" --> to the system date
while(date_str = strstr(c, "<!--#echo var=\"date\"-->")){
date_change(&c, date_str, date);
}
write(g, c, strlen(c));
close(g);
// -------------------------------- //
close(f);
return 0;
}
943
asked Dec 05 '25 12:12
Your code is not trying to modify the buffer that was passed into it. Instead, you've created a static array that you are writing into, and you're then returning that static array (without actually looking at the return value).
82
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