Can I force a default special member function to be noexcept?

Question

The following structure fails to compile under C++11 due to the fact that I have declared the move assignment operator as noexcept:

struct foo
{
  std::vector<int> data;
  foo& operator=(foo&&) noexcept = default;
};

The default move assignment operator generated by the compiler is noexcept(false) due to the fact that std::vector<int>'s move assignment is also noexcept(false). This in turn is due to the fact that the default allocator has std::allocator_traits<T>:: propagate_on_container_move_assignment set to std::false_type. See also this question.

I believe this has been fixed in C++14 (see library defect 2103).

My question is, is there a way for me to force noexcept upon the default move assignment assignment operator without having to define it myself?

If this is not possible, is there a way I can trick the std::vector<int> into being noexcept move assignable so that noexcept(true) is passed through to my struct?