UIImage has a read-only property CGImage. I have to read its pixels to a memory block and edit them and then make a new UIImage to replace the old one. I want to know if there is a way bypass the read-only property and edit those pixels directly.
Thanks.
Thanks all. I have found a way to do it. Write a class with those method:
-(void)preProcess:(UIImage*)srcImage {
    m_Context = ...// Created by calling CGBitmapContextCreate(...)
    ...
    CGContextDrawImage(m_Context, rect, srcImage.CGImage);
    m_Bits = (unsigned char*)CGBitmapContextGetData (mContext);
}
-(void)postProcess {
    CGContextRelease(m_Context);
    free(m_Bits);
}
-(UIImage*)doProcess:(CGPoint)pt {// just a example 
    unsigned char* ppxl = m_Bits + ...
    // do something...
    CGImageRef imRef = CGBitmapContextCreateImage(mContext);
    return [UIImage imageWithCGImage:imRef];
}
And preProcess and postProcess are called just once.
For the more obtuse among us (read: future me) here's some working code based on Itay and Dave R's answers. It starts with a UIImage and ends with a modified UIImage:
    // load image
    UIImage *image      = [UIImage imageNamed:@"test.png"];
    CGImageRef imageRef = image.CGImage;
    NSData *data        = (NSData *)CGDataProviderCopyData(CGImageGetDataProvider(imageRef));
    char *pixels        = (char *)[data bytes];
    // this is where you manipulate the individual pixels
    // assumes a 4 byte pixel consisting of rgb and alpha
    // for PNGs without transparency use i+=3 and remove int a
    for(int i = 0; i < [data length]; i += 4)
    {
        int r = i;
        int g = i+1;
        int b = i+2;
        int a = i+3;
        pixels[r]   = 0; // eg. remove red
        pixels[g]   = pixels[g];
        pixels[b]   = pixels[b];
        pixels[a]   = pixels[a];
    }
    // create a new image from the modified pixel data
    size_t width                    = CGImageGetWidth(imageRef);
    size_t height                   = CGImageGetHeight(imageRef);
    size_t bitsPerComponent         = CGImageGetBitsPerComponent(imageRef);
    size_t bitsPerPixel             = CGImageGetBitsPerPixel(imageRef);
    size_t bytesPerRow              = CGImageGetBytesPerRow(imageRef);
    CGColorSpaceRef colorspace      = CGColorSpaceCreateDeviceRGB();
    CGBitmapInfo bitmapInfo         = CGImageGetBitmapInfo(imageRef);
    CGDataProviderRef provider      = CGDataProviderCreateWithData(NULL, pixels, [data length], NULL);
    CGImageRef newImageRef = CGImageCreate (
                              width,
                              height,
                              bitsPerComponent,
                              bitsPerPixel,
                              bytesPerRow,
                              colorspace,
                              bitmapInfo,
                              provider,
                              NULL,
                              false,
                              kCGRenderingIntentDefault
                              );
    // the modified image
    UIImage *newImage   = [UIImage imageWithCGImage:newImageRef];
    // cleanup
    free(pixels);
    CGImageRelease(imageRef);
    CGColorSpaceRelease(colorspace);
    CGDataProviderRelease(provider);
    CGImageRelease(newImageRef);
The short answer is no. However, you say you have to make a copy anyhow, so why not just get an NSData object and manipulate its bytes.
From the Apple docs on UIImage:
Because image objects are immutable, they also do not provide direct access to their underlying image data. However, you can get an NSData object containing either a PNG or JPEG representation of the image data using the UIImagePNGRepresentation and UIImageJPEGRepresentation functions.
To get the data as a PNG, use:
NSData * UIImagePNGRepresentation (
   UIImage *image
);
for JPEG, use:
NSData * UIImageJPEGRepresentation (
   UIImage *image,
   CGFloat compressionQuality
);
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