I just learned about variadic templates in C++. I implemented it, but I want to know, can it do the following?
If I want a function with a variable number of arguments, I could do that:
template <typename... Ts>
f(Ts... args);
But I lose type safety (I don't know the type of the arguments).
What if I know my function needs only float as arguments? I want to make sure at compile-time that every argument is the type I want.
So these are my questions:
Is there a way to force a certain type with variadic templates (something like this)?
template <float... Fs>
f(Fs... args); // unlimited number of arguments but only float
If not, is there a way to check it at compile-time? static_assert(std::is_same<A,B>) is fine in most cases, but it doesn't work for templated classes (like for my use case):
template <typename T, uint16_t dimension>
class Vector
{
template <typename... Ts>
Vector(Ts... args)
{
static_assert(sizeof...(args) == dimension);
static_assert(std::is_same_v<Ts..., T>()); //doesn't work because Ts will
//develop into a lot of template
//arguments. Just putting Ts doesn't
//work either.
}
}
Ps: Yes I could use std::vector or std::array as arguments, but that's not really the point. Plus, I want to keep the beautiful Vector(2.0, 1.0, 0.0) syntax, not using curly braces.
template <typename T, uint16_t dimension>
class MyVector
{
public:
template <typename... Ts>
MyVector(Ts... args)
{
static_assert(sizeof...(args) == dimension);
static_assert((std::is_same<T,Ts>::value && ...) );
}
};
Can also use the unary right fold expression as provided in C++17 https://en.cppreference.com/w/cpp/language/fold
This essentially does
std::is_same<T,Ts_1>::value && ( std::is_same<T,Ts_2>::value && ... std::is_same<T,Ts_n>::value ) ...)
And works also when the parameter pack Ts is empty. Quote from the reference link:
" Logical AND (&&). The value for the empty pack is true"
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