C *char pointer to char array

Question

I have a *char pointer and a char array. How can I put the value of the pointer in the char array? I've tried

uint8_t i;
char a[10];
char *b = "abcdefghi";
for(i = 0; i < 9; i++)
{
    a[i] = b[i];
}
printf("%s", a);

But this doesn't work.

Answer 1

The size of a is 10, so is the length of b(including the null terminator). Change

for(i = 0; i < 9; i++)

to

for(i = 0; i < 10; i++)