Can Anyone help with bellman ford algorithm in java to calculate the shortest path from the source vertex.
I would also like the final updated predecessor nodes to be printed for each nodes after traversing all the edges and after all iterations This is my code
import java.io.*;
import java.util.*;
public class BellmanFord {
LinkedList<Edge> edges;
int d[];
int n,e,s;
final int INFINITY=999;
private static class Edge {
int u,v,w;
public Edge(int a, int b, int c) {
u=a;
v=b;
w=c;
}
}
BellmanFord() throws IOException {
int item;
edges = new LinkedList<Edge>();
BufferedReader inp = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Enter number of vertices ");
n = Integer.parseInt(inp.readLine());
System.out.println("Cost Matrix");
for(int i=0;i<n;i++) {
for(int j=0;j<n;j++) {
item = Integer.parseInt(inp.readLine());
if(item != 0)
edges.add(new Edge(i,j,item));
}
}
e = edges.size();
d = new int[n];
System.out.print("Enter the source vertex ");
s = Integer.parseInt(inp.readLine());
}
void relax() {
int i,j;
for(i=0;i<n;++i)
d[i]=INFINITY;
d[s] = 0;
for (i = 0; i < n - 1; ++i) {
for (j = 0; j < e; ++j) { //here i am calculating the shortest path
if (d[edges.get(j).u] + edges.get(j).w < d[edges.get(j).v]) {
d[edges.get(j).v] = d[edges.get(j).u] + edges.get(j).w;
}
}
}
}
boolean cycle() {
int j;
for (j = 0; j < e; ++j)
if (d[edges.get(j).u] + edges.get(j).w < d[edges.get(j).v])
return false;
return true;
}
public static void main(String args[]) throws IOException {
BellmanFord r = new BellmanFord();
r.relax();
if(r.cycle()) {
for(int i=0;i<r.n;i++)
System.out.println(r.s+" ==> "+r.d[i]);
} else {
System.out.println(" There is a negative edge cycle ");
}
}
}
According to the standard algorithm, I think you should introduce an array for the predecessors:
int[] p = new int[n];
Initialize in your relax
function:
for(i=0;i<n;++i) {
d[i] = INFINITY;
p[i] = -1;
}
And update together with the distance:
for (i = 0; i < n - 1; ++i) {
for (j = 0; j < e; ++j) { //here i am calculating the shortest path
if (d[edges.get(j).u] + edges.get(j).w < d[edges.get(j).v]) {
d[edges.get(j).v] = d[edges.get(j).u] + edges.get(j).w;
p[edges.get(j).v] = edges.get(j).u;
}
}
}
And print:
for (int i = 0; i < n; i++) {
System.out.println("Vertex " + i " has predecessor " + p[i]);
}
EDIT Since you seem to have some problem with my code snippets, here the full working code:
import java.io.*;
import java.util.*;
public class BellmanFord {
LinkedList<Edge> edges;
int d[], p[];
int n,e,s;
final int INFINITY=999;
private static class Edge {
int u,v,w;
public Edge(int a, int b, int c) {
u=a;
v=b;
w=c;
}
}
BellmanFord () throws IOException {
int item;
edges = new LinkedList<Edge>();
BufferedReader inp = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Enter number of vertices ");
n = Integer.parseInt(inp.readLine());
System.out.println("Cost Matrix");
for(int i=0;i<n;i++) {
for(int j=0;j<n;j++) {
item = Integer.parseInt(inp.readLine());
if(item != 0)
edges.add(new Edge(i,j,item));
}
}
e = edges.size();
d = new int[n];
p = new int[n];
System.out.print("Enter the source vertex ");
s = Integer.parseInt(inp.readLine());
}
void relax() {
int i,j;
for(i=0;i<n;++i) {
d[i]=INFINITY;
p[i] = -1;
}
d[s] = 0;
for (i = 0; i < n - 1; ++i) {
for (j = 0; j < e; ++j) { //here i am calculating the shortest path
if (d[edges.get(j).u] + edges.get(j).w < d[edges.get(j).v]) {
d[edges.get(j).v] = d[edges.get(j).u] + edges.get(j).w;
p[edges.get(j).v] = edges.get(j).u;
}
}
}
}
boolean cycle() {
int j;
for (j = 0; j < e; ++j)
if (d[edges.get(j).u] + edges.get(j).w < d[edges.get(j).v])
return false;
return true;
}
void print() {
for (int i = 0; i < n; i++) {
System.out.println("Vertex " + i + " has predecessor " + p[i]);
}
}
public static void main(String args[]) throws IOException {
BellmanFord r = new BellmanFord ();
r.relax();
if(r.cycle()) {
for(int i=0;i<r.n;i++)
System.out.println(r.s+" ==> "+r.d[i]);
} else {
System.out.println(" There is a negative edge cycle ");
}
r.print();
}
}
Input:
Enter number of vertices 3
Cost Matrix
0
99
1
4
0
2
2
4
0
Enter the source vertex 0
Output:
0 ==> 0
0 ==> 5
0 ==> 1
Vertex 0 has predecessor -1
Vertex 1 has predecessor 2
Vertex 2 has predecessor 0
Which is as expected
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