How can I avoid a null return value when invoking the greatest function with a null parameter. Example:
select greatest(1,null,2) from dual
The above returns null, but I want 2.
I don't want to use nvl and also not something like:
coalesce(greatest(term1,term2,term3), greatest(term1,term2), term1).
Is there is any other way of avoiding the null return value?
Oracle Setup:
CREATE FUNCTION greatest_ignore_null(
vals SYS.ODCINUMBERLIST
) RETURN NUMBER
IS
output NUMBER := NULL;
BEGIN
FOR i IN 1 .. vals.COUNT LOOP
IF vals(i) IS NOT NULL AND ( output IS NULL OR vals(i) > output ) THEN
output := vals(i);
END IF;
END LOOP;
RETURN output;
END;
/
Query:
SELECT greatest_ignore_null(
SYS.ODCINUMBERLIST( 1, NULL, 3, NULL, 2 )
) AS largest
FROM DUAL;
Output:
LARGEST
-------
3
One solution is to use a SELECT query with a common table expression to put the values into something resembling a table, and then use the SQL MAX function in a manner similar to the following:
DECLARE
n1 NUMBER := 1;
n2 NUMBER := NULL;
n3 NUMBER := 3;
nMin NUMBER := -99999999999999999999999999999999999999e125;
nMax NUMBER;
BEGIN
WITH CTE AS (SELECT n1 AS N FROM DUAL
UNION ALL
SELECT n2 AS N FROM DUAL
UNION ALL
SELECT n3 AS N FROM DUAL)
SELECT MAX(COALESCE(n, nMin))
INTO nMax
FROM CTE;
DBMS_OUTPUT.PUT_LINE('nMax=' || nMax);
END;
The above uses COALESCE, which is the ANSI equivalent of NVL. If you don't want to use either NVL or COALESCE you can use a CASE-expression instead:
WITH CTE AS (SELECT n1 AS N FROM DUAL
UNION ALL
SELECT n2 AS N FROM DUAL
UNION ALL
SELECT n3 AS N FROM DUAL)
SELECT MAX(CASE
WHEN N IS NULL THEN nMin
ELSE N
END)
INTO nMax
FROM CTE;
Best of luck.
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