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Average Time Difference Between Two Dates PER Group

I have a dataframe with users and their visit dates. I'm trying to find the average time difference between visits per group. The output would be in days or fraction of a day

require(lubridate)
so <- data.frame(visit_dates = c("12/4/2016","12/6/2016","12/7/2016","12/3/2016","12/7/2016","12/10/2016"), person = c("1","1","1","2","2","2"))


so$visit_dates <- mdy(format(as.POSIXct(strptime(so$visit_dates,"%m/%d/%Y",tz = "")),format = "%m/%d/%Y"))

The output would look something like:

person    avgTimeBetweenVisit
1                 2.5
2                 3.5
like image 914
daveDo Avatar asked Feb 27 '26 02:02

daveDo


2 Answers

Try data.table:

require(lubridate)
require(data.table)
so <- data.frame(visit_dates = c("12/4/2016","12/6/2016","12/7/2016","12/3/2016","12/7/2016","12/10/2016"), person = c("1","1","1","2","2","2"))


so$visit_dates <- mdy(format(as.POSIXct(strptime(so$visit_dates,"%m/%d/%Y",tz = "")),format = "%m/%d/%Y"))
so <- data.table(so, key = c("person", "visit_dates"))
res <- so[, .(avgTimeBetweenVisit = mean(diff(visit_dates))), by = person]
print(res)
# person avgTimeBetweenVisit
# 1:      1            1.5 days
# 2:      2            3.5 days
like image 174
Bulat Avatar answered Mar 01 '26 15:03

Bulat


What about that:

so %>%
  group_by(person)%>% 
  mutate(Difference = visit_dates - lag(visit_dates)) %>%
  summarize(mean_time = mean(Difference, na.rm=TRUE))

That link helped me with the 'diff' problem. diff operation within a group, after a dplyr::group_by()

like image 29
sluedtke Avatar answered Mar 01 '26 14:03

sluedtke



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